# “In any network containing more than one sources of e.m.f. the current in any branch is the algebraic sum of a number of individual fictitious currents (the number being equal to the number of sources of e.m.f.), each of which is due to separate action of each source of e.m.f., taken in order, when the remaining sources of e.m.f. are replaced by conductors, the resistances of which are equal to the internal resistances of the respective sources”. The above statement is associated with:? with Answer - Electrical Engineering Mcqs | TestPrep

> Solved MCQ: “In any network containing more than one sources of e.m.f. the current in any branch is the algebraic sum of a number of individual fictitious currents (the number being equal to the number of sources of e.m.f.), each of which is due to separate action of each source of e.m.f., taken in order, when the remaining sources of e.m.f. are replaced by conductors, the resistances of which are equal to the internal resistances of the respective sources”. The above statement is associated with: Correct Answer: C. Superposition theorem. Verified answer explanation for FPSC, PPSC, MDCAT, NTS, and CSS competitive exam preparation.

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# “In any network containing more than one sources of e.m.f. the current in any branch is the algebraic sum of a number of individual fictitious currents (the number being equal to the number of sources of e.m.f.), each of which is due to separate action of each source of e.m.f., taken in order, when the remaining sources of e.m.f. are replaced by conductors, the resistances of which are equal to the internal resistances of the respective sources”. The above statement is associated with:

Direct Answer & Quick Reference

The correct option is **C. Superposition theorem**.

A. Thevenin’s theorem

B. Norton’s theorem

C. Superposition theorem **(Correct Answer)**

D. None of the above

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Verified Key: C. Superposition theorem
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*Source: https://test-prep.blog/mcq/in-any-network-containing-more-than-one-sources-of-emf-the-current-in-any-branch-4c42e004-f29f-4b36-86b0-172d5c9a7175*
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