# Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg. K, entropy of saturated vapour = 7.2234 kJ/kg. K) The exit condition of steam is _____ ? with Answer - Chemical Engineering Mcqs | TestPrep

> Solved MCQ: Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg. K, entropy of saturated vapour = 7.2234 kJ/kg. K) The exit condition of steam is _____ ? Correct Answer: A. Superheated vapour. Verified answer explanation for FPSC, PPSC, MDCAT, NTS, and CSS competitive exam preparation.

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# Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg. K, entropy of saturated vapour = 7.2234 kJ/kg. K) The exit condition of steam is _____ ?

Direct Answer & Quick Reference

The correct option is **A. Superheated vapour**.

A. Superheated vapour **(Correct Answer)**

B. Partially condensed vapour with quality of 0.9

C. Saturated vapour

D. Partially condensed vapour with quality of 0.1

✨ Explain with AI

Verified Key: A. Superheated vapour
Solved by 2,398+ students

Verified against official examination board answer keys and standard curriculum textbooks.

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